Spam is of concem to anyone with an email address Several co
Solution
a)
Formulating the null and alternatuve hypotheses,
Ho: p <= 0.02
Ha: p > 0.02
***********
b)
We should use a z test for population proportion.
***********
c)
As this is a 0.10 level, right tailed test, then by table/technology,
Reject Ho when z > 1.281551566. [ANSWER]
*************
d)
As we see, the hypothesized po = 0.02
Getting the point estimate of p, p^,
p^ = x / n = 0.040106952
Getting the standard error of p^, sp,
sp = sqrt[po (1 - po)/n] = 0.007239228
Getting the z statistic,
z = (p^ - po)/sp = 2.777499592 [ANSWER]
*************
e)
As this is a 1 tailed test, then, getting the p value,
p = 0.002738945 [ANSWER]
*************
f)
As z > 1.281, and P < 0.1, we Reject Ho.
There is significant evidence that the proportion of spam getting through is greater than 2% at 0.1 level. [CONCLUSION]
