Maria and Eduardo are traveling to a business conference The
Maria and Eduardo are traveling to a business conference. The trip takes 2 hr for Maria and 2.5 hr for Eduardo, since he lives 40 mi farther away. Eduardo travels 5 mph faster than Maria. Find their average rates.
Solution
Let s = M\'s speed
 Then
 (s+5) = E\'s speed
 :
 Write a distance equation: Dist = Time * speed
 :
 E\'s trip - M\'s trip = 40
 2.5(s+5) - 2s = 40
 :
 2.5s + 12.5 - 2s = 40
 :
 2.5s - 2s = 40 - 12.5
 :
 .5s = 27.5
 :
 s = 27.5/.5
 :
 s = 55 mph is M\'s speed
 then
 55 + 5 = 60 mph is E\'s speed
 :
 :
 Check our solutions by finding the distances
 M: 2 * 55 = 110 mi
 E: 2.5 * 60 = 150 mi which is 40 mi further

