find the volume bound by yx3 y0 x1 about y1 please show st

find the volume bound by y=x^3 , y=0, x=1 ; about y=1

please show steps. thanks

y = x^3 x = y^1/3 V = 2pintegral of rf(y)dy.....limit from 0 to 1 r =1-y f(y) = y^1/3 V = 2p integral of (1-y)y^1/3 V = 2p integral of (y^1/3 - y^4/3)dy integrating wrt y V = 2p [3/4 y^4/3 - 3/7 y^7/3] apply limits V = 2p[3/4 - 3/7] V = 2p*9/28 V = 9p/14 V = 2.02