Find the area of the following triangles a Sides of 10 and 2

Find the area of the following triangles: a. Sides of 10 and 22 and included angle of 10 degree: b. Sides of 11, 100 and 101:

Solution

2 a) Area of triangle = (1/2)*side1*side2*sin(angle between sides 1 and 2)

= (1/2)*(10*22)*(sin10)

= 19.10 squnit

b) Area of triangle = (1/2)*side1*side2*sin(angle between sides 1 and 2)

= (1/2)*10*100*sin101

= 490.81 squnits