ALGEBRA 2 Alternate Exam 5continued 1S Circle the letter of

ALGEBRA 2 Alternate Exam 5-continued 1S. Circle the letter of the function represented by the graph. x-4x+3 x +2x-3 x-2x-3 x +4x+3 p , 4.3 19. List any asymptotes (vertical or honizontal) that this graph has. even odd neither 20. This graph is (circle one): 21) This graph has the same end behavior as the graph of y= 22. Circle the function represented by the graph 16-x 23. List any asymptotes (vertical or ) that this graph has It has a h 24This graph is (circle one): odd neither O (25) This graph has the same end behavior as the graph of y 65 This graph has the same end behavior as FILL IN YOUR NAME AND THE OTHER REQUIRED INFORMATION ON EACH PAGE OF THE EXAMAND MAIL THE EXAM TO THE SCHOOL A-(1083)-07/14-05 AMERICAN SCHOOL Lansing.IL.

Solution

18 ) Graph has x intercepts at x=-1 and x =3

So, numerator = (x+1)(x-3) = x^2 -2x -3

So, Option C

19 ) y = (x^2 -2x-3)/(3x -3)

Vertical asymtote : 3x -3 = 0 ---> x = 1

20) The graph is neither even nor odd

21) The end behaviour of y = (x^2 -2x-3)/(3x -3) can be found using long division

y = x/3 -1/3 - 4/(3x -3)

there is an oblique asymptote at y= x/3 -1/3

So, end behaviour is y = x/3 -1/3

22) The function has vertical asymtotes at x= -3 and x=3

Denominator of function : x^2 -9

Option A : y = 2x^2/(x^2 -9)

25) The end behaviour behaves as: y =2x^2/x^2 = 2 as x---> infinity

y = 2