c What is the probability that a students grade is less than
Solution
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c)
We first get the z score for the critical value. As z = (x - u) / s, then as
x = critical value = 70
u = mean = 50
s = standard deviation = 10
Thus,
z = (x - u) / s = 2
Thus, using a table/technology, the left tailed area of this is
P(z < 2 ) = 0.977249868 [ANSWER]
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d)
We first get the z score for the two values. As z = (x - u) / s, then as
x1 = lower bound = 70
x2 = upper bound = 80
u = mean = 50
s = standard deviation = 10
Thus, the two z scores are
z1 = lower z score = (x1 - u)/s = 2
z2 = upper z score = (x2 - u) / s = 3
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.977249868
P(z < z2) = 0.998650102
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.021400234 [ANSWER]
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e)
First, we get the z score from the given left tailed area. As
Left tailed area = 0.90
Then, using table or technology,
z = 1.281551566
As x = u + z * s,
where
u = mean = 50
z = the critical z score = 1.281551566
s = standard deviation = 10
Then
x = critical value = 62.81551566 [ANSWER]

