n Figure 5 40 m Q813 marks If Fu is the tension at the lowes

n Figure 5 40 m Q813 marks) If Fu is the tension at the lowest point of the cable (b), w is the uniform distributed load hanging from the cable and L is the span of the cable, which equation gives the shape of the cable: 8 m B m a) ysw. /(2. 20kN/m Figure 5 e) None of the abave Q9[S morks] is the force F equal to: a) 179.4 kN b) 1134.7 kN c) 666.7 kN d) 1372.6 kN el 343.1 kN The steel structure shown in Figure 6 is supported by two pins at A and B. All members have a cross section in the form of a square with edge length equal to 25mm. The steel Young\'s Modulus is E = 200 GPa and the thermal expansion factor is -1.1 x 10 src. Q10 [3 marks] Is the force in EG equal to: al 9.7 kN (Tension) b) 20 kN (Compression) c) 20 kN (Tension) d) 9.7 kN (Compression) e) 15 kN (Tension) Figure 6 Page 5 of 9 TURN OVER

Solution

Answer:

Q8). The equation for the given shape is b) none of the above

                and the correct equation is y = w.x² / (2.L)

Q9). Force F_x is given by the formula & F_x = c. 666.7 KN

                                                        Tmax =(wL/8h) Square root (L² + 16h² )

                                                                 = (20*40/8*8)/ square root (40² + 16²)

                                                                 = (800/64)/ square root (1600+1024)

                                                                 = 12.5 * 53.33 =666.70

Q10). Answer is a. 9.7 KN (T)

sum of forces = 0

    -12+GE Cos30 = 0

                     GE =12*.866

                           = 9.7KN (T)