Homework SourseSuppose that the eye color and wing shape genes assort indep
Suppose that the eye color and wing shape genes assort independently (they are not linked, i.e., they are located on different chromosomes). In a mating between a female with the genotype w+m+/wm and a male of genotype wm/wm what percentage of the F1 progeny will have a non-parental genotype?
A. 100
B. 50
C. 25
D. 75
Solution
Answer:
B. 50
Explanation:
w+m+/wm X wm/wm
Total parental progeny = 50%
Total non-parental progeny = 50%
| wm | |
| w+m+ | w+m+/wm (parental progeny)-25% |
| w+m | w+m/wm (non-parental progeny)-25% |
| wm+ | wm+/wm(non-parental progeny)-25% |
| wm | wm/wm (parental progeny)-25% |
