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Solve for x: logx+log(x-15)=2

Solution

Given: logx+log(x-15)=2

         log(x(x-15))=2

         log(x^2-15x)=2

I am assuming you mean log base 10. In that case, we have:

       x^2-15x=10^2

       x^2-15x=100

        x^2-15x-100=0

           x^2-20x+5x-100=0

   x(x-20)+5(x-20)=0

(x-20)(x+5)=0

         i,e x=20,-5