A sample space contains three outcomes A B and C Which of th

A sample space contains three outcomes, A, B, and C.

Which of the following could be a      legitimate assignment of probabilities to the outcomes?

            A) P(A) = 0.2 P(B)=0.4       P(C)=0.6

            B) P(A) = 0.2 P(B)=0.2         P(C)=0.6

            C) P(A) = 2     P(B) = 3          P(C) = 1

            D) P(A) = 0.3 P(B) = 0.3       P(C) = 0.3

Solution

a legitimate assignment of probabilities to the outcomes will be the values that when you sum all of them (3)

you need to have a value of 1

A)

P(A)+P(B)+P(C) = 0.2+0.4+0.6 = 1.2

this is not a legitimate assignment of probabilities

B)

P(A)+P(B)+P(C) = 0.2+0.2 + 0.6 = 1

this is a legitimate assignment of probabilities

C)

this cant be you have more than 1

d)

you have minus than 1 you have 0.9

this is not

THE ANSWER IS B)