020 kg of orange is cooled from 20 degree C to 5 degree C in

0.20 kg of orange is cooled from 20 degree C to 5 degree C in a refrigerator. The amount of heat transferred from the orange to the refrigerator is closest to 7.40 kJ. 11.25 kJ. 24.85 kJ. 55.55 kJ. 112.50 kJ.

Solution

given data,m=02.kg

t2=20c

t1=5c

cp=3.77KJ/kgk

Q=mcp(t2-t1)

=0.2*3.77*15

=11.31KJ/kg