Find the length of an are that subtends a central angle of 1

Find the length of an are that subtends a central angle of 135 degree in a circle of radius 2 mi. No decimal answers. Find two positive angles and two negative angles that are conterminal to the following angles in standard position State your answer in radians for problems given in radian and degrees if given in degrees. -45 degree 11 pi/6

Solution

3) arc length L =r

radius r= 2mi ,^o=135^o

in radians =(135^o/180^o)*

arc length L =2*(135^o/180^o)*

arc length L =2*(3/4)*

arc length L =3/2 mi

4)

a) -45^o

positive angles  

-45^o+360^o=315^o

-45^o+360^o+360^o=675^o

negative angles

-45^o-360^o=-405^o

-45^o-360^o-360^o=-765^o

b)

11/6

positive angles

(11/6)+2 =23/6

(11/6)+2+2 =35/6

negative angles

(11/6)-2 =-/6

(11/6)-2-2  =-13/6