Suppose that following the CME it is found that at an altitu

Suppose that following the CME it is found that at an altitude of 2500 m the electric field has magnitude 1100 N/C and at an altitude of 1500 m the magnitude is 3700 N/C. In both cases the direction of the electric field is vertically toward the earth\'s surface. Find the net amount of charge (also indicate the sign of the charge) contained in a cube with horizontal forces at altitudes of 2500 and 1500 m. Assume that the surface of the earth is flat and horizontal.3.34 Times 10^(-2) C. -5.76 Times 10^(-2) C. 7.69 Times 10^(3) pC. 7.47 Times 10^-3) pC -5.19 Times 10^(3) pC. The values of C_1, C_2, C_3, C_4 and C_5 are 250, 450, 330, 570, and 190 microfarad =, respectively. Determine the equivalent capacitance of c_2, C_4 and C_5. 9.15 Times 10^(-4) F.4.55 Times 10^(-7) F. 4.67 Times 10^(-6) F. 5,15 Times 10^(-4) F. 5.93 Times 10^(-4) F. Determine the equivalent capacitance C_A - B between terminals A and B. 9.93 Times 10^(-4) nF. 4.55 Times 10^(-7) F. 1.15 Times 10^(-4) F. 5.15 Times 10^(-4) F 7.93 Times 10^(-4) F. A rod in the shape of rectangular solid has cross-sectional area of 17.8 cm^2, length of 5.20 cm resistivity of 25.8 Times 10^-8 m. The material from which the block is made has 5.95 Times 10^28 conduction electrons/m^3. A potential differences of 52.6 m V is maintained between its ends. What is the current in the block? 6.98 Times 10^(3) A. 4.65 Times 10^(-1) A 5.81 Times 10^(-1) ma. 6.71 Times 10^(-30 mA. 9.31 times 10^(-2) A. Assume that the current density in the rod is uniform. What is its value? 6.761 Times 10^(-2) A. 4.65 Times 10^(-3)A. 5.81 Times 10^(-1) A.m^2. 6.71 Times 10^(-6) a/M^2. 3.92 Times 10^6a/m^2.

Solution

5.

C₄ and C₅ are in series ,so

1/C₄₅ =1/570 + 1/190

C₄₅=142.5 uF

C₂ and C₄₅ are in parallel

C₂₄₅=142.5 + 410 =552.5 uF

C₂₄₅ =5.53*10^-4 F

b)

Answer is 1.15*10^-4 F

C₁ ,C₂₄₅ and C₃ are in parallel ,so equivalent capacitance

1/C_ab =1/552.5 + 1/250 +1/390

C_ab=119.4 uF =1.19*10^-4 F

6.

Resistance

R=pL/A =(34.5*10^-8)*0.052/(17.8*10^-4)

R=1.007*10^-5 ohms

Current in the block

I=E/R =52.6*10^-3/1.007*10^-5

I=5.22*10³ A

b.

Current density

I=J/A =5.22*10³/(17.8*10^-4)

I=2.93*10⁶A/m²