At Dayton OH what is the solar time corresponding to 1100 AM

At Dayton, OH, what is the solar time corresponding to 11:00 AM (dock time) on Feb. 3? (Dayton is located at 84 degree W longitude) Using the previous problem for Dayton, OH, what is the solar altitude angle and azimuth angle? (The latitude of Dayton is 39.7 degree N) Using the previous problem for Dayton, OH, what is the solar angle of incidence on a surface tilted at 45 degree from the horizontal, facing southeast? If during the day there is 200 W/m^2 solar from 8:00 am to 10:00 am, 600 W/m^2 from 10:00 am to 12:00 noon, 900 W/m^2 from 12:00 noon to 3:00 pm, 300 W/m^2 from 3:00 pm to 6:00 pm, and 100 W/m^2 from 6:00 pm to 7:00 pm, how many peak sun hours were there in that day?

Solution

Dear i am giving u steps with example how to calculate solar time, kindly do calculation.

Thanks

Step 1

Find the local solar time meridian. This is used to adjust for where you are on the Earth. It is 15 degrees, which is the difference between local time and Greenwich mean time in hours. For example, in New York City with daylight savings time it is 4 hours earlier than Greenwich mean time, so this is 15-4 = -60.

Step 2

Find the number of days since the start of the year; call this d. For example, today is June 18th, which is 168 days since the start of the year.

Step 3

Subtract 81 from d and multiply by 360/365. In the example, 168-81 = 84 and 84*360/365 = 82.85. Call this B

Step 4

Calculate 9.87sin(2B) - 7.53cos(B) - 1.58sin(B). In the example, sin(2B) = sin(165.7) = 0.247; cos(B) = cos(82.85) = 0.128 and sin(B) = 0.992. 9.870.247 - 7.530.128 - 1.580.992 = 2.437 - 0.964 - 1.567 = -0.094. Call this E.

Step 5

Calculate the time correction factor. This is 4(local solar time meridian - longitude) + E. In the example, the longitude for New York City is 73 degrees west, or -73 degrees. So this is 4(-60-(-73)) -0.094 = 4(-60+73) - 0.094 = 413 - 0.094 = 51.806. This is given in minutes.

Step 6

Add the time correction factor to the local time to get local solar time. The local solar time in New York City on June 18, 2011 is 51.806 minutes later than local time.