Find probability that the first ticket is an even number Fin
Solution
1) Probability that first ticket is an even number = (favourable outcomes)/(total outcomes) = (3)/(6) = 1/2
2) We need to find the probability that the second ticket is odd number given the first ticket was 7. If the first ticket was 7, then we have total outcomes = 5 and leftover odd outcomes = 2. Thereforefore, the required probability that the second ticket is odd given the first ticket was 7 = 2/5
3) Probability that the second ticket is an odd number = (1/2)(2/5)+(1/2)(3/5) = 2/10+3/10 = 5/10 = 1/2
4) Probability that the first ticket is an even number and second ticket is an odd number:
Since first ticket is an even number. Therefore, in the second draw, the total outcomes are 5 and favourable outcomes are 3. Hence, the required probability = 3/5
