Given the values n21 p06 and m12 compute the probability of

Given the values n=21, p=0.6, and m=12, compute the probability of m successes in n independent trials of a binary experiment.

For n=21, p=0.6 and m=12, the probability of m successes in n independent trials on a binary

Solution

The probability of getting exactly m success in n trials, with the probability of success on a single trial being p is:

           =21C12 * (0.6)^12 * (0.4)^9

           = 293930 * 0.002176782336 * 0.000262144=0.1667254

hence , probability = 16.67% or 0.1667