Homework Soursea particle starts at point 50 at t0 and moves along the xaxi
a particle starts at point (5,0) at t=0 and moves along the x-axis in such a way that at time t>0 its velocity is given by v(t)= t/(1+t^2). Determine the maximum velocity attained by the particle
Solution
the answer is:
v\' = [ (1+t2) - t(2t) ]/(1 + t2 )2
v\'(t) = 0
=> t = 1
v(t=1) = 1/2 m/s
so the maximum velocity will be 1/2m/s
