Suppose that giraffe heights follow a normal distribution wi
Suppose that giraffe heights follow a normal distribution with mean 18
Solution
a.) how tall must a giraffe be to be in the top 15% of giraffes?
P(X>c)=0.15
--> P((X-mean)/s <(c-18)/2.5) =1-0.15=0.85
--> P(Z<(c-18)/2.5) =0.85
--> (c-18)/2.5= 1.04 (from standard normal table)
So c= 18+1.04*2.5=20.6
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b) what range of heights (low - high) mark off the middle 60% of giraffe heights?
Given a=1-0.6=0.4, Z(0.4/2)=Z(0.2)=0.84 (from standard normal table)
So the lower value is
mean -Z*s =18-0.84*2.5 =15.9
So the high value is
mean + Z*s =18+0.84*2.5 =20.1
So the range = 20.1- 15.9 =4.2
