GIVEN side r 284317m side s 150780 side t 201397m FIND An

GIVEN: side r = 284.317m; side s = 150.780; side t = 201.397m FIND: Angle R Angle S Angle T GIVEN: Angle FOX=29 degree 57\'35\"; side FOX-PJ6=167.28chains; side PJ6-CEY=102.47chains (ch)

Solution

by law of cosines

cosR=(s2+t2-r2)/(2st)

cosR=[150.782+201.3972-284.3172]/(2*150.78*201.397)

cosR=-0.2888

R=106.8o

R=106o48\'

cosS=(r2+t2-s2)/(2rt)

cosS=[284.3172+201.3972-150.782]/(2*284.317.78*201.397)

cosS=0.86152

S=30.51o

S=30o30\'36\"

cosT=(r2+s2-t2)/(2rs)

cosT=[284.3172+150.782-201.3972]/(2*284.317.78*150.78)

cosT=0.7349

T=42.7o

T=42o 42\'

 GIVEN: side r = 284.317m; side s = 150.780; side t = 201.397m FIND: Angle R Angle S Angle T GIVEN: Angle FOX=29 degree 57\'35\

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