Homework SourseA consumer organization estimates that over a 1 year period
A consumer organization estimates that over a 1 year period 16% of cars will need to be repaired once, 6% will need repairs twice, and 3% will require three or more repairs. What is the probability that a car chosen at random will need
A. No repairs
B. No more than one repair
C. Some repairs
A consumer organization estimates that over a 1 year period 16% of cars will need to be repaired once, 6% will need repairs twice, and 3% will require three or more repairs. What is the probability that a car chosen at random will need
A. No repairs
B. No more than one repair
C. Some repairs
A. No repairs
B. No more than one repair
C. Some repairs
Solution
P(1 repair)=0.16
P(2 repairs) = 0.06
P(more than 2 repairs) = 0.03
A.
P(no repairs) = 1-(P(one repair)+P(2 repairs)+P(more than 2 repairs))
P(no repairs) = 1 - 0.16 - 0.06 - 0.03
P(no repairs) = 0.75
B.
P(more than one repair) = P(2 repairs)+P(more than 2 repairs)
P(more than one repair) = 0.06+0.03 = 0.09
C.
P(some repairs) = P(more than 2 repairs) = 0.03
