The crosses you will study can be a cross of the wildtype st

The crosses you will study can be a cross of the wild-type strain with one of the mutants or it can be a cross of two mutant strains. One of the mutant traits is sex-linked. You must determine how each mutant differs from the wild-type, whether the mutations are dominant or recessive, and autosomal or sex-linked. To complete the lab, there are some questions that you need to answer based on the basics of genetics: How do you determine which allele is dominant and recessive? How do you determine if it is a monohybrid or dihybrid cross? How do you determine if the trait is autosomal or sex-linked? How do you determine the expected phenotypes in the F2 flies?

Solution

1. The dominant alleles are the alleles thar are express their trait or phenotype both in homozygous (TT) and heterozygous (Tt) conditions. Where as Recessive alleles express only in homozygous (tt) conditions

2. If we crossed two alternative forms of one gene then it is Monohybrid cross. It gives Genotypic ratio of 1:2:1 and Phenotype ratio of 3:1. On the other hand, if we cross 4 alternative forms of 2 genes, then it is Dihybrid cross. It gives genotypic ratio of 1:2:1:2:4:2:1:2:1 and Phenotype ratio of 9:3:3:1

3. If the trait is Autosomal, it distributed equally in both sexes throughout generations. On the other hand if trait is allosomal or sexual, it only or prefarably affect particular sex among generations

4. The formula used for no. Of expected phenotypes in F2 is 2^n. Here n is type of cross. In case of monohybrid cross, the expected different pheno types are 2 ( 2^1 = 2) and in dihybrid cross, the expected different phenotypes are 4 (2^2 = 4)