H0m6 against H1m6 variance known find P value for Z0205 Z018

H0:m=6 against H1:m6 variance known find P value for Z0=2.05 Z0=-1.84 Z0=0.4

H0:m=9 against H1:m>9 variance known find P value for Z0=2.05 Z0=-1.84 Z0=0.4

Solution

A)

H0:m=6 against H1:m6 variance known find P value for
Z0=2.05

As H1 used =/=, then this is a two tailed test.

Using table/technology, the two tailed P value is, by table/technology,

P = 0.040364431 [ANSWER]

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Z0=-1.84

As H1 used =/=, then this is a two tailed test.

Using table/technology, the two tailed P value is, by table/technology,

P = 0.065768237 [ANSWER]

********************************

Z0=0.4

As H1 used =/=, then this is a two tailed test.

Using table/technology, the two tailed P value is, by table/technology,

P = 0.689156517 [ANSWER]

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b)

H0:m=9 against H1:m>9 variance known find P value for Z0=2.05 Z0=-1.84 Z0=0.4

As H1 used >, then this is a right tailed test.

Thus, getting the right tailed areas, by table/technology,

For z = 2.05,

P = 0.020182215 [ANSWER]

For z = -1.84,

P = 0.967115881 [ANSWER]

For z = 0.4,

P = 0.344578258 [ANSWER]