Given that Z1 20040i ohm 3 Z2 50130i ohm the total impedan

Given that Z_1 = 200-40i ohm 3 Z_2 = 50-130i ohm the total impedance the phase angel the total line current

Solution

Ans)

Given Z₁=200-j40 and Z₂=60-j130

as both the impedances in parallel Z_T=Z₁||Z₂=Z₁*Z₂/(Z₁+Z₂)=(200-j40)*(60-j130)/(200-j40+60-j130)

Z_T=68.35-j64.54 ohms

A)

Z_T=94<-43.36^o ohms

B)

Phase angle is 43.36^o

C)

Line current I=V/Z_T=12/(68.35-j64.54)=0.0928+j0.0876 A

I=0.128<43.36^o A