1 How many threedigit numbers are there that have the proper
Solution
note we are suppose to answer one question at a time so i will give u answer for 3rd
for rest u have to repost the question again.
3) total 3 digit number which can be formed with repeatition are 9*10*10 = 900 as at 1st place we can only have 9 digits as 0 cant come at 1st place
so total 3 digit numbers are 900
we have to find the the 3 digit number such that one digit is repeating
now case 1 if the gigit at 1st and 2nd place are repeating
then at 1st place we have 9 options
then at second options we have only 1 option as the number which will come at 1st place will come at 2nd place
3rd place we will heve again 9 options
so total numbers in this case will be 81(9*9*1)
in case 2
we will have the same number 2nd and 3rd number
again total number will be 81
similarly in case 3rd the number 1st and 3rd will repeat
now total number are again 81
so total number will be 81+81+81 = 243
now if we consider the case when if the digit at 1st is repeating with digit at 2nd and 3rd place then total number will be 9
hence 243+9 = 252

