The number of viewers of American Idol has a mean of 31 mill

The number of viewers of American Idol has a mean of 31 million with a standard deviation of 4 million. Assume this distribution follows a normal distribution.

  

  

Have between 33 and 39 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

  

  

Have at least 24 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

  

  

Exceed 43 million viewers? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

  

  

The number of viewers of American Idol has a mean of 31 million with a standard deviation of 4 million. Assume this distribution follows a normal distribution.

Solution

(in million) mu 31 X is normal Probability sigma 4 a) 3324 Z>-1.75 0.5+0.4599 0.9599 c) x>43 z>3 0 0