Losttime accidents occur in a company at a mean rate of 08 p
Lost-time accidents occur in a company at a mean rate of 0.8 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be at least 3 ? Round your answer to four decimal places.
Solution
The mean per day is 0.8, so for 9 days, the mean is 0.8*9 = 7.2.
Note that P(at least x) = 1 - P(at most x - 1).          
           
 Using a cumulative poisson distribution table or technology, matching          
           
 u = the mean number of successes =    7.2      
           
 x = our critical value of successes =    3      
           
 Then the cumulative probability of P(at most x - 1) from a table/technology is          
           
 P(at most   2   ) =    0.025473508
           
 Thus, the probability of at least   3   successes is  
           
 P(at least   3   ) =    0.974526492 = 0.9745 [answer]

