Losttime accidents occur in a company at a mean rate of 08 p
Lost-time accidents occur in a company at a mean rate of 0.8 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be at least 3 ? Round your answer to four decimal places.
Solution
The mean per day is 0.8, so for 9 days, the mean is 0.8*9 = 7.2.
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative poisson distribution table or technology, matching
u = the mean number of successes = 7.2
x = our critical value of successes = 3
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 2 ) = 0.025473508
Thus, the probability of at least 3 successes is
P(at least 3 ) = 0.974526492 = 0.9745 [answer]
