O oll12 points I Previous Answers serpset9 27 qq005nva a My

O oll.12 points I Previous Answers serpset9 27 qq.005.nva a. My Notes o Ask Your Tea For the two shown in the figure below, rank the current values at points a through f from greatest to least. (Use only the symbols for example la Ib Ic, etc.) 80 W 60 W

Solution

Power , P = V^2/R

Now, as both the bulbs are connected to the same voltage source

So, their resistances (R) must be inversely proportional to their resepective Powers(P)

Now, Power of the bottom bulb is double that of the other bulb.

So, Reistance of the bottom bulb must be half of that of the top bulb

So, current in the bottom bulb must be double that of top.

Now, as the current through the battery is sum of the currents in both the bulbs.

So, current in the battery is highest followed by the current in bottom bulb and then the top bulb

So, (Ia = Ib) > (Ic = Id) > (Ie = If) <------- ANSWER