A study was done to find out how long on average it takes Fr
Solution
a. What is the point estimate for the mean of all assignment times?
point estimate= 4.296875
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b. Construct a 90% confidence interval for the mean amount of times it takes to complete the weekly assignments in this math class. (Show your formula set up or your calculator command.)
Given a=1-0.9=0.1, Z(0.05) = 1.645 (from standard normal table)
The sample standard deviation =1.588971
So the lower bound is
xbar - Z*s/vn =4.296875 -1.645*1.588971/sqrt(32) =3.834806
So the upper bound is
xbar + Z*s/vn =4.296875 +1.645*1.588971/sqrt(32) =4.758944
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c. What is the margin of error?
The margin of error =Z*s/vn
=1.645*1.588971/sqrt(32)
=0.4620691
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d. List two ways to make this margin of error smaller.
Increase sample size
Decrease the confidence interval level
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e. Interpret the confidence interval you got in part b in the context of the problem. Use complete sentences.
We have 90% confident that the population mean amount of times it takes to complete the weekly assignments in this math class will be within this interval.
