A thermocouple produces an output voltage mV when there is a

A thermocouple produces an output voltage (mV) when there is a temperature difference between the head (T2) and the gauge (T1). The transfer function is given as [V=0.032(T1-T2)+0.0000062(T1^2-T2^2)] where V is in mV and T is in °C. If the head temperature is 200ºC and the gauge temperature is at 10ºC, what is the output voltage in mV?

Solution

V=0.032(T1-T2)+0.0000062(T1^2-T2^2)] T1=10 degree c T2= 200 degree c

V= V=0.032(10-200)+0.0000062(10^2-200^2)] mV =-6.32 mV