Test 4 a circular orbit RE2 Chalf radius ofEarth above the E

Test 4 a circular orbit RE/2 Chalf radius ofEarth) above the Earth\'s surface. 1. A satellite is 6.37 x 10 m, mass of Earth What is the linear speed of the satellite? ORadius of Earth 5.98 x 1024 kg, G-6.67 x 10 Nm kg Gn m/s)

Solution

Ans1.

Linear speed = sqrt(G*M_e/R) = sqrt(2* G*M_e/R_e)

=sqrt(2 x 6.6 X 10^-11 x 5.98 x 10²⁴ /6.67 x 10⁶) = 1.11 x 10⁴ m/s

Ans 3

Weight of object in the air = 33 N

Mass of the object = 33/9.8 = 3.37 Kg

Loss of Weight in Water = 33-21 = 12 Newton

Weight of Water Displaced = 12 Newton

Mass of displaced Water =12/9.8 = 1.22 Kg

Density of Water = 1000 Kg/m³

Volume of Water Displaced = 1.22/1000 = 1.22x10^-3m³ = Volume of the object

Therefore Density of the object = 3.37/{1.22x10^-3}

= 2762 Kg/m³

Ans 4

Pressure = gh = Vg/A

P_g = Vg/A (ground level)

At height radius of pipe is reduced to half, so volume is increase by 4 times.

P_h = 4 Vg/A (at height) = 4 gh = 4 x 1000 x 9.8 x 14 = 548 k Pa