What weight of water is required to fill a 27gallon aquarium

What weight of water is required to fill a 27-gallon aquarium? Express your answer using two significant figures.

Solution

! gallon = 3.785 litres = 3.785 x 10^-3 m³

So, V (total Volume) =27 gallons = 27 x 3.785 x 10^-3 m³ = 0.1046 m³

Density of water , d = 1000 Kg/m³

W (weight of water)= d x V x g = 1000 x 0.1046 x 9.81 = 1.026 kN