For the circuit shown in the figure Figure 1 find the readin

For the circuit shown in the figure (Figure 1) find the reading of the idealized ammeter if the battery has an internal resistance of 3.56 Ohm.

Solution

First finding the equivalent resistance

45 and 15 ohms are in parallel

1/R =1/45 + 1/15

R=11.25 ohms

18 ohms ,3.56 ohms and 11.25 ohms are in series ,so equivalent resistance

R_eq=18+3.56+11.25

R_eq=32.81 ohms

So Current flowing through the circuit i.e reading of ammeter is

I =V/R_eq =25/32.81

I=0.762 A