To assess Mendels law of segregation using tomatoes a truebr

To assess Mendel\'s law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (SS). The heterozygous F1 tall plants (Ss) were crossed to produce two sets of F2 data, as follows. What is the chi square value for set II? Enter your answer to two decimal places. Can the numbers produced in Set II be attributable to chance? Answer yes or no. Your answer should look, like the following (a number of three significant figures, a semicolon, and either yes or no)

Solution

For tall, observed= 750; Expected= total x 3/4= 960 x 3/4= 720

For short, observed= 210; Expected= total x 1/4= 960 x 1/4 =240

For tall-

chi square= (observed-expected)²/ expected

=(30 x30)/720 =900/720 = 1.25

For short-

chi square= (observed-expected)²/ expected

=(-30 x -30)/240 = 900/240 =3.75

Total chi square = 1.25 +3.75 = 5.00

degree of freedom= 2-1= 1

Hence, data is a poor fit