Homework SourseUse the following POM crashing output to answer Q39 Q40 Tim
Use the following POM crashing output to answer Q39 - Q40. Times are in DAYS.
Crashing Solution
Activity
Normal time
Crash time
Normal Cost
Crash Cost
Crash cost/pd
Crash by
Crash cost
Project
26
17
A
7
6
1500
1800
300
1
300
B
12
9
3000
4050
350
1
350
C
9
6
2500
3700
400
2
800
D
12
6
2800
5200
400
6
2400
E
3
1
500
1100
300
2
600
F
1
1
0
0
0
0
0
G
3
1
600
1500
450
2
900
H
3
2
300
750
450
0
0
I
4
4
0
0
0
0
0
TOTALS
11200
5350
Crashing Solution
Project time
Period cost
Cumulative cost
A
B
C
D
E
F
G
H
I
26
0
0
25
300
300
1
24
400
700
1
1
23
400
1100
1
2
22
400
1500
1
3
21
450
1950
1
3
1
20
450
2400
1
3
2
19
700
3100
1
4
1
2
18
1100
4200
1
1
5
2
2
17
1150
5350
1
1
2
6
2
2
1) What would you do to crash this project to 20 days?
A. Crash A
| Crashing Solution | |||||||
| Activity | Normal time | Crash time | Normal Cost | Crash Cost | Crash cost/pd | Crash by | Crash cost |
| Project | 26 | 17 | |||||
| A | 7 | 6 | 1500 | 1800 | 300 | 1 | 300 |
| B | 12 | 9 | 3000 | 4050 | 350 | 1 | 350 |
| C | 9 | 6 | 2500 | 3700 | 400 | 2 | 800 |
| D | 12 | 6 | 2800 | 5200 | 400 | 6 | 2400 |
| E | 3 | 1 | 500 | 1100 | 300 | 2 | 600 |
| F | 1 | 1 | 0 | 0 | 0 | 0 | 0 |
| G | 3 | 1 | 600 | 1500 | 450 | 2 | 900 |
| H | 3 | 2 | 300 | 750 | 450 | 0 | 0 |
| I | 4 | 4 | 0 | 0 | 0 | 0 | 0 |
| TOTALS | 11200 | 5350 |
Solution
1.
as shown in 2nd table
at 20 days duration
A for 1 day, D for 3 day and G for 2 day crashed.
2.
Option A: Crash project time to 20 days, which saves $600 compared to normal completion time of 26 days
is correct
| Days | Cost due to crashing | Panelty | Net | Saving |
| 17 | 5350 | 0 | 5350 | -850 |
| 18 | 4200 | 500 | 4700 | -200 |
| 19 | 3100 | 1000 | 4100 | 400 |
| 20 | 2400 | 1500 | 3900 | 600 |
| 21 | 1950 | 2000 | 3950 | 550 |
| 22 | 1500 | 2500 | 4000 | 500 |
| 23 | 1100 | 3000 | 4100 | 400 |
| 24 | 700 | 3500 | 4200 | 300 |
| 25 | 300 | 4000 | 4300 | 200 |
| 26 | 0 | 4500 | 4500 | 0 |
