What is the exact output of the following code Solutioninclu

What is the exact output of the following code?

Solution

#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;

int main(int argc, char const *argv[])
{
   int i,j;

   i=fork();

   for (j = 0; j <3; ++j)
   {
       if(i==0&& j==0)
       {
           sleep(3);
           cout<<\"Cats\ \";
       }
       else if(i==0)
       {
           sleep(2);
           cout<<\"Dogs\ \";
       }
       else
       {
           sleep(2);
           cout<<\"Raining\ \";
       }
   }
   return 0;
}

Output:

Raining
Cats
Raining
Dogs
Raining

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Explanation:when we call fork there are 2 proceess runing child and parent.In for loop,parent process will first run and print \"Raining\" at the same time child process in background will run at j==0 and i==0 because fork returns 0 for child process hence prints \"Cats\".In next iteration,parent will run and print \"Raining\" but at this time j!=0 but i==0 in background child process hence it will print \"Dogs\",In last iteration,it will print \"Raining \" only becuase it is only condition that will be satisfied