Homework SourseIn a study conducted to investigate browsing activity by sho
In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each classification, the study obtained a measure to determine how comfortable eight shoppers were in a store. Higher scores indicated greater comfort. Analysis showed that SSE = 24.5 and SSTR = 9.33.
Construct the ANOVA table (to 2 decimals, if necessary).
Use a 0.05 level of significance.
What is the critical value (to 2 decimals)?
3.47
What is the value of the test statistic (to 2 decimals, if necessary).
The p-value is - Select your answer
-less than .01
between .01 and .025
between .025 and .05
between .05 and .10
greater than .10Item 12
What is your conclusion?
- Select your answer -At a 95% confidence level, I can conclude that the mean comfort scores are not all the same for the browser groups.
-----At a 95% confidence level, I cannot conclude that the mean comfort scores are not all the same for the browser groups.Item 13
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
| Treatments | 9.33 | 2 | 4.67 | |
| Error | 24.5 | 21 | 1.17 | |
| Total | 33.83 | 23 |
Solution
In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a non browser, light browser, or heavy browser. For each classification, the study obtained a measure to determine how comfortable eight shoppers were in a store. Higher scores indicated greater comfort. Analysis showed that SSE = 24.5 and SSTR = 9.33.
Construct the ANOVA table (to 2 decimals, if necessary).
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
Treatments
9.33
2
4.67
4.67/1.17 = 3.99
Error
24.5
21
1.17
Total
33.83
23
Use a 0.05 level of significance.
What is the critical value (to 2 decimals)?
3.47
What is the value of the test statistic (to 2 decimals, if necessary).
3.99
The p-value is - Select your answer( P=0.034)
-less than .01
between .01 and .025
between .025 and .05
between .05 and .10
greater than .10Item 12
we reject the null hypothesis at 0.05 level.
What is your conclusion?
- Select your answer -At a 95% confidence level, I can conclude that the mean comfort scores are not all the same for the browser groups.
-----At a 95% confidence level, I cannot conclude that the mean comfort scores are not all the same for the browser groups.Item 13
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
| Treatments | 9.33 | 2 | 4.67 | 4.67/1.17 = 3.99 |
| Error | 24.5 | 21 | 1.17 | |
| Total | 33.83 | 23 |
