An outdoor PV lighting system will provide lighting for a wa
Solution
Energy Consumed by the 35 fixtures each containing 6 W LED on for 15 hours a day is equal to
E = 6*15*35 = 3150 Wh /day in winter season;
Battery system required which should store energy sufficient for 3 days is
Eb = 3150 *3 = 9450 Wh
Considering loss and dicharge percentage EbT = 9450/(0.98*0.9*0.8) = 13392.85 Wh
Ampere hour rating of battery is Ah = EbT/Vb = 13392.85/12 = 1116.07 Ah battery system is required.
Solar Photovoltaic panels required is considering Watt rating of each panel of 200 W.
Given degradation factor for PVs is 0.9 , Power delivered per each panel at instant of peak sun is
P = 200*0.9 = 180 W
Given each winter day has peak sun for 4 hours.
Each PV will generate energy of Epv = 180*4 = 720 Wh.
Required energy to be stored is EbT = 13392.85 Wh
No,of solar panels required is N = EbT/Epv = 13392.85/720 = 18.6 = 19 Photovoltaic panels.

