The scores on an achievement test have a mean of 500 and a s

The scores on an achievement test have a mean of 500 and a standard deviation of 51. After completing a special tutoring program, a group of 24 students had an average score of 519. Test to determine if the tutoring program produced a significant increase in the students’ scores using = 0.04 and the prob-value approach.

Solution

X-bar = 500

SD = 51

n=24

alpha = 0.04

Null Hypothesis : mu >500

z = ( 519 -500) / (51/sqrt(24))

= 1.83

P-value = 1 -0.9664 = 0.0336 Answer

Since 0.0336 < 0.04 , we will reject the null hypothesis.

Alternate Hypothesis :