Homework SourseCan you please provide direction for the following Steps for
Can you please provide direction for the following? Steps for process and are needed to provide clarity. Not looking for just the answer please.
Information
A Travel Agency decided to run a contest to advertise their business. They asked a marketing research firm to determine what would be the most popular vacation for people in the immediate geographic area, to help them get the maximum interest in the travel agency and in the contest. The research firm asked a random sample of individuals: “Where would you like to take a vacation?” and got the results below. Analyze the data and make a recommendation for the travel agency.
Note on this problem you are still doing the CHI, but as you move across from left to right for each row, the steps for the CHI are laid out for you. Item 32 then is the CHI value! Just that easy. For Expected, add up the Observed and divide by the number of rows of data (3).
Vacation Type
O (observed)
O-E
(O-E)2
(O-E)2/E
Las Vegas
22
Mountains
46
Seashore
28
Use the Above Data to complete Items 30-39.
Your df are number of rows minus one, (3-1), and because there is only one column, there isn’t a chance for a score to randomly fall into another column, so we leave the column figure at just 1. So you compute df = (3-1)(1). Or 3,1.
Total from the last column:
What is the Expected value: E?
What is the Calculated Chi Square for this analysis?
What are the degrees of freedom?
N =
What is the tabled value for Chi-Square?
Is the result significant? Why?
What do you conclude?
To analyze continuous data that is being compared between three or more groups, you should use the ________ statistic
To analyze continuous data that is being compared between two sets of scores from one group, collected before \"pre\" and after \"post\" the Independent Variable, you should use the _______ statistic.
| Vacation Type | O (observed) | O-E | (O-E)2 | (O-E)2/E |
| Las Vegas | 22 | |||
| Mountains | 46 | |||
| Seashore | 28 |
Solution
Set up null and alternate hypothesis
H0:People have equal preference for all 3 places
Ha: Atleast two have different preferences
------------------------------------------------
Prepare contingency table as follows:
df = 3-1 = 2
The P-Value is 0.007635. The result is significant at p < 0.01.
Hence all places do not have equal preferences and this is statistically evident.
Fill in the blanks:
t or z
paired t test or paired z test.
| Vacation Type | O (observed) | E(Expected) | O-E | (O-E)2 | (O-E)2/E |
| Las Vegas | 22 | 32 | -10 | 100 | 3.125 |
| Mountains | 46 | 32 | 14 | 196 | 6.125 |
| Seashore | 28 | 32 | -4 | 16 | 0.5 |
| Total | 96 | 96 | 0 | 312 | 9.75 |
