A researcher predicts that married males watch significantly

A researcher predicts that married males watch significantly more television than unmarried males. In order to test this hypothesis, the researcher measures the amount of television viewed by 42 randomly selected males; 22 are married (mean amount of television viewed = 3.33 hours per day, s = 2.64) and 20 are unmarried (mean amount of television viewed = 2.72 hours per day, s = 3.43). If alpha is set at .05, the critical value of the test statistic is:

Solution

Null, significantly less television than unmarried males Ho: p1 = p2
Alternate, significantly more television than unmarried males them H1: p1 > p2
Test Statistic
Sample 1 : X1 =22, n1 =42, P1= X1/n1=0.524
Sample 2 : X2 =20, n2 =42, P2= X2/n2=0.476
Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
P^=0.5
Q^ Value For Proportion= 1-P^=0.5
we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
Zo =(0.524-0.476)/Sqrt((0.5*0.5(1/42+1/42))
Zo =0.436
| Zo | =0.436
Critical Value
The Value of |Z | at LOS 0.05% is 1.645
We got |Zo| =0.436 & | Z | =1.645
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Right Tail -Ha : ( P > 0.4364 ) = 0.33126
Hence Value of P0.05 < 0.33126,Here We Do not Reject Ho