A car A left city X traveling 60 mph2 hours later a car B le

A car A left city X traveling 60 mph.2 hours later a car B leaves City X, traveling the same road at 70 mph. When will car B reach car A? How far will each car have traveled?

Solution

This is an RTD problem. Here is a table based on the given information
cars . . . . . . . . . rate . . . . . . . . .time . . . . . . . . distance
A. . . . . . . . . . . .60. . . . . . . . . . x . . . . . . . . . . . .60x
B. . . . . . . . . . . . 70 . . . . . . . . . .x -2 . . . . . . . . . 70x - 140
since the distances are equal, we get
60x = 70x - 140
subtract 70x to get
-10x = -140
x = 14
It will take 14 hours for B to reach A
60*14 = 840 miles