Given the function Find vertical asymptote horizontal asympt

Given the function

Find vertical asymptote

horizontal asymptote

slant asymptote

(If the function does not have an asymptote state: none)

Solution

y = (2x-4)/(x^2 -25)

Vertical asymtote: equate denominator =0

x^2 -25 =0

x = -5 ; x=5

Vertical asymtote : x = -5 ; x=5

Since the degree is greater in the denominator than in the numerator, the y-values will be dragged down to the x-axis, and the horizontal asymptote is therefore \"y = 0\".

So, horizontal asymtote : y=0

No slant asymtote