Find the arc length S and xy coordinates in mm given that th

Find the arc length \"S\" and x,y coordinates in mm, given that theta= pi/6 and r= 12.

PLEASE SHOW WORK!

Solution

r= 12    theta =pi/6

x = r cos theta = 12 cos (pi/6) = 6sqrt3

y= r sin theta =12 sin(pi/6) =6

point is (6sqrt3,6)

Arc length, s= r * theta

                s= 12 * pi/6 = 2pi = 6.28