Can you conclude a relationship between the class of vertebr

Can you conclude a relationship between the class of vertebrate and whether it is endangered or threatened? Use the 0.05 level of significance. Is there a different result for the 0.01 level of significance?

Can you conclude a relationship between the class of vertebrate and whether it is endangered or threatened? Use the 0.05 level of significance. Is there a different result for the 0.01 level of significance?

Solution

Can you conclude a relationship between the class of vertebrate and whether it is endangered or threatened? Use the 0.05 level of significance. Is there a different result for the 0.01 level of significance?

Null hypothesis: There is no relationship between the class of vertebrate and whether it is endangered or threatened.

Alternate hypothesis: There is relationship between the class of vertebrate and whether it is endangered or threatened.

Chi-Square Test

Observed Frequencies

Column variable

Calculations

Row variable

C1

C2

C3

C4

C5

Total

fo-fe

R1

68

76

14

13

76

247

13.7805

15.0867

-10.7669

-2.3957

-15.7046

R2

13

15

23

10

61

122

-13.7805

-15.0867

10.7669

2.3957

15.7046

Total

81

91

37

23

137

369

Expected Frequencies

Column variable

Row variable

C1

C2

C3

C4

C5

Total

(fo-fe)^2/fe

R1

54.2195

60.9133

24.7669

15.3957

91.7046

247

3.5025

3.7366

4.6807

0.3728

2.6894

R2

26.7805

30.0867

12.2331

7.6043

45.2954

122

7.0911

7.5651

9.4765

0.7547

5.4450

Total

81

91

37

23

137

369

Data

Level of Significance

0.05

Number of Rows

2

Number of Columns

5

Degrees of Freedom

4

Results

Critical Value

9.488

Chi-Square Test Statistic

45.315

Table value of chi square with 4 Df at 0.05 level of significance =9.488

The calculate chi square value = 45.315 > 9.488

The null hypothesis is rejected

We conclude at 0.05 level that there is relationship between the class of vertebrate and whether it is endangered or threatened.

Table value of chi square with 4 Df at 0.01 level of significance =13.277

The calculate chi square value = 45.315 > 13.277

The null hypothesis is rejected

We conclude at 0.01 level that there is relationship between the class of vertebrate and whether it is endangered or threatened.

Chi-Square Test
Observed Frequencies
	Column variable			Calculations
Row variable	C1	C2	C3	C4	C5	Total		fo-fe
R1	68	76	14	13	76	247		13.7805	15.0867	-10.7669	-2.3957	-15.7046
R2	13	15	23	10	61	122		-13.7805	-15.0867	10.7669	2.3957	15.7046
Total	81	91	37	23	137	369
Expected Frequencies
	Column variable
Row variable	C1	C2	C3	C4	C5	Total		(fo-fe)^2/fe
R1	54.2195	60.9133	24.7669	15.3957	91.7046	247		3.5025	3.7366	4.6807	0.3728	2.6894
R2	26.7805	30.0867	12.2331	7.6043	45.2954	122		7.0911	7.5651	9.4765	0.7547	5.4450
Total	81	91	37	23	137	369
Data
Level of Significance	0.05
Number of Rows	2
Number of Columns	5
Degrees of Freedom	4
Results
Critical Value	9.488
Chi-Square Test Statistic	45.315