Write a C program or C program that will work with condition

Write a C++ program( or C program): that will work with conditional statements to implement simple calculator program.:

Input: Enter a math expression of the form : a op b, where a and b are operands and op is one of the following: +, -, *, / . Output: Given a valid expression, your program should clculate the result and reprint the entire expression and its result. [example: Enter precision:2 ., Enter expression: 3/2..... result: 3.00/2.00 = 1.50........ ]

Error checking: Your program should print an error under any of the following conditions: - any input that is incorrectly formatted therefore can not be read correctly using scanf(). nVals = scanf(\"%d %d %d\"); - User tries to divide by zero. - the mathematical operator entered is not a valid operator. - the precision is not a valid value(must be>/ 0) ( must be greater than or equal to zero:0)   

Solution

main.cpp

# include <iostream>
using namespace std;
int main()
{
    char op;
    float num1,num2;
    cout << \"Enter operator either + or - or * or /: \";
    cin >> op;
    cout<<endl;
    cout << \"Enter two operands: \";
    cin >> num1 >> num2;
    cout<<endl;
    switch(op) {
        case \'+\':
            cout <<endl<< num1 <<op<<num2<<\" = \"<<num1+num2;
            break;
        case \'-\':
            cout <<endl<< num1<<op<<num2<<\" = \"<< num1-num2;
            break;
        case \'*\':
            cout << endl<<num1<<op<<num2<<\" = \"<< num1*num2;
            break;
        case \'/\':
            cout << endl<< num1<<op<<num2<<\" = \"<<num1/num2;
            break;
        default:
            cout <<endl<< \"Error! operator is not correct\";
            break;
    }
    return 0;
}

Output: