Please provide steps to the answere i appreciate your work d

Please provide steps to the answere.. i appreciate your work deeply

A 0.12-mu F capacitor, initially uncharged, is connectcd in series with a 10-kohm resistor and a 12-V battery of negligible internal resistance. Approximately how long does it take the capacitor to reach 90% of its final charge? 5.5 ms 2.8 ms 1.4 ms 3.5 ms 6.9 ms The switch S is initially at position a for a long time. It is then switched to position b. Describe what happens to the light bulb as a function of time when the switch is flipped from a to b? The light bulb was on but goes off immediately. The light bulb was off and stays off. The light bulb was on but its brightness decreases with time and eventually goes off. The light bulb was on and stays on. The light bulb was off. It then lights up but the brightness decreases with time and eventually goes off. A capacitor is made with two strips of metal foil, each 2.5 cm wide by 50 cm long, with a 0.70-pm thick strip of paper (k = 3.7) sandwiched between them. The capacitor is rolled up to save space. What is the capacitance of this device? Use the following to answer questions 23 - 24: A 10.0-muF capacitor is charged so that the potential difference between its plates is 10.0 V. A 5.0-pF capacitor is similarly charged so that the potential difference between its plates is 5.0 V. The two charged capacitors are then connected to each other in parallel with positive plate connected to positive plate and negative plate connected to negative plate. How much charge flows from one capacitor to the other when the capacitors arc connected? What is the final potential difference across the plates of the capacitors when they are connected in parallel? 5.0 V 6.7 V 7.5 V 10 V A parallel plate capacitor has a potential difference between its plates of 1.6 V and a plate separation distance of 2.5 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.4 is inserted between the plates? 110 V/m 170 V/m 190 V/m 240 V/m 290 V/m

Solution

1

Time constant

t = RC = 1.2*10^-3 s

Charge is expressed as

Q= Qo [1-e^-time/t]

Time=2.8 *10^-3 s = 2.8 ms