A researcher studied the flexibility of 10 women in an aerob
A researcher studied the flexibility of 10 women in an aerobic exercise class, 8 women in a modern dance class, and a control group of 10 women. One measurement she made was on the degree of spinal extension. Measurements were made before and after a 16 week training program and the difference between the two was calculated. Summary statistics for the data are given in Table 1 below. Let the significance level ? alpha = 0.1.
A) Complete the ANOVA table by filling in the missing cells. Use 2-decimal precision where appropriate. MStreatment has been reported for you.
The null/alternative pair appropriate for this ANOVA setting is as follows:
Ho: ?1 = ?2 = ?3
Ha: At least one ?i differs
The p-value for this hypothesis test is: _____________
| Source of Variation | df | Sum of Squares | Mean Square | F |
| Treatment | 3.68 | |||
| Error | Not meaningful | |||
| Total | Not meaningful | Not meaningful |
Solution
Let there be n observations and m treatments. Here n = 10+8+10 = 28 and m = 3.
Knowing any of the one value (SSError,SSTotal,MSError or F), the rest can be calculated.
p-value can be calculated using the FDIST function in excel {=FDIST(F,2,25)}
| Source of Variation | Degrees of freedom | Sum of Squares | Mean Square | F Ratio |
| Treatment | m-1=3-1=2 | MST x (m-1) = 3.68 x 2 = 7.36 | 3.68 | MSTreatment/MSError |
| Error | n-m=28-3=25 | SSError | MSError | x |
| Total | n-1=28-1=27 | SSTreatment+SSError=SSTotal | x | x |
