A biologist examines a series of cells and counts 160 cells
A biologist examines a series of cells and counts 160 cells in interphase, 20 cells in prophase, 6 cells in prometaphase, 2 cells in metaphase, 7 cells in anaphase, and 5 cells in telophase. If the complete cell cycle requires 24 hours, what is the average duration (in hours) of the M phase in these cells?
Solution
Stage
Total number of cell counted
Proportion of cell at every stage (number of cells/ total number of cells)
Average duration (in hours ) = (multiply 24 hours by the proportion of cells at that stage)
Interphase
160
0.80
19.2
Prophase
20
0.10
2.4
Prometaphase
6
0.03
0.72
Metaphase
2
0.01
0.24
Anaphase
7
0.035
0.84
Telophase
5
0.025
0.6
Totals
200
1.0
24
The M- phase average duration is mainly assessed by summing up the total hours spent in every stage of mitotic division. In the above given cells, M phase is lasts for 4.8 hours. The metaphase is going to require 0.24 hours 14.4 minutes
| Stage | Total number of cell counted | Proportion of cell at every stage (number of cells/ total number of cells) | Average duration (in hours ) = (multiply 24 hours by the proportion of cells at that stage) |
| Interphase | 160 | 0.80 | 19.2 |
| Prophase | 20 | 0.10 | 2.4 |
| Prometaphase | 6 | 0.03 | 0.72 |
| Metaphase | 2 | 0.01 | 0.24 |
| Anaphase | 7 | 0.035 | 0.84 |
| Telophase | 5 | 0.025 | 0.6 |
| Totals | 200 | 1.0 | 24 |

