shawn begins walking to nathans house at 3mph Nathan leaves
shawn begins walking to nathan\'s house at 3mph. Nathan leaves his house at the same time walking towards shawn\'s house at 2mph.. how long will it be before they meet if the distance between the houses is 4 miles?
Solution
D=RT
4=(3+2)T
4=5T
T=4/5
T=.8 HOURS IS THE WALKING TIME.
